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JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

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Application +4 | -1

An electron is liberated from the lower of the two large parallel metal plates separated by a distance of

20 \mathrm{~mm}

. The upper plate has a potential of

+2400 \mathrm{~V}

relative to the lower plate. How long does the electron take to reach the upper plate? Take

\frac{e}{m}

of electrons

1.8 \times 10^{11} \mathrm{~C} \mathrm{~kg}^{-1}

.

View answer and explanation

Correct option: A

1.4 \times 10^{-9} \mathrm{~s}

Option A (

1.4 \times 10^{-9} \mathrm{~s}

) is correct because it is the time calculated using kinematics and the electric field between the plates.

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