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JEE MATHEMATICS MCQ: PERMUTATIONS

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Application +4 | -1
If a,b,ca, b, c are three natural numbers in AP and a+b+c=21a+b+c=21, then the possible number of values of the ordered triplet (a,b,c)(a, b, c) is
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Correct option: C
13
Option C (13) is correct because it represents the number of possible values for the ordered triplet (a, b, c) when a, b, and c are in AP and their sum is 21.

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