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JEE MATHEMATICS MCQ: ELLIPSE

1 Hard
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Application +4 | -1
The length of the smallest intercept made by the coordinate axes on any tangent to the ellipse x2a2+y2b2=1\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1, is
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Correct option: A
a+ba + b
Option A (a+ba + b) is correct because it represents the minimum length of the intercept made by the coordinate axes on any tangent to the ellipse.

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