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NEET UG PHYSICS MCQ: MAGNETIC EFFECT OF CURRENT

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A water drop of mass 3.2ร—10โˆ’18kg3.2 \times {10^{ - 18}}kg and carrying a charge of 1.6ร—10โˆ’19C1.6 \times {10^{ - 19}}C is suspended stationary between two plates of an electric field. Given g=10m/s2g = 10m/{s^2} , the intensity of the electric field required is
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Correct option: A
200โ€‰Vm200\,\frac{V}{m}
Option A is correct because the electric force on the charged water drop must balance its weight for it to remain stationary, leading to an electric field intensity of 200 V/m.

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