The end product of the decay of $_{90}{\rm{T}}{{\rm{h}}^{232}}\,\,{\rm{is}}\,{\,_{82}}{\rm{P}}{{\rm{b}}^{208}}$. The number of $\alpha \,\,{\rm{and}}\,\,\beta $-particles emitted are respectively

NEET UG PHYSICS MCQ: NUCLEI

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The end product of the decay of

_{90}\mathrm{T}{\mathrm{h}^{232}}\,\,\mathrm{is}\,{\,_{82}}\mathrm{P}{\mathrm{b}^{208}}

. The number of

\alpha \,\,\mathrm{and}\,\,\beta

-particles emitted are respectively

View answer and explanation

Correct option: A

\mathrm{6,4}

Option A (

\mathrm{6,4}

) is correct because each alpha particle emission reduces the mass number by 4 and the atomic number by 2, while each beta-minus particle emission increases the atomic number by 1.

More Questions from NUCLEI

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The ratio of the nuclear radii of elements with mass numbers

\mathrm{216}

and

\mathrm{125}

is In a hypothetical fission reaction

{ }_{92} X^{236} \rightarrow{ }_{56} Y^{141}+{ }_{36} Z^{92}+3 R

The identity of emitted particles

({R})

is: The radius of the nucleus of the atom with A=216 is (take

{R_0}\; = \mathrm{ }1.3fm

) The correct sequence of the increasing wavelength of the given radiation sources is Which of the following nuclear fragments corresponding to nuclear fission between neutron

\left({ }_0^1 \mathrm{n}\right)

and uranium isotope

\left({ }_{92}^{235} \mathrm{U}\right)

is correct: Which of the following has the mass closest in value to that of the positron

1\,\,a.m.u = 931\,\,MeV