JEE MATHEMATICS MCQ: LIMITS

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Analyzing +4 | -1

\lim \limits_{{x \rightarrow 0}}\left[1+x \log \left(1+b^2\right)\right]^{(1 i x)}=2 b \sin ^2 \theta, b > 0

and

\theta \in(-\pi, \pi]

then the value of

\theta

View answer and explanation

Correct option: D

\pm \frac{\pi}{2}

Option D (

\pm \frac{\pi}{2}

) is correct because by evaluating the limit and solving the resulting equation, the value of

\theta

is found to be

\pm \frac{\pi}{2}

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