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JEE PHYSICS MCQ: MECHANICAL PROPERTIES OF FLUIDS

1 Medium

1 of 1

Application +4 | -1

A drop of water of volume

V

is pressed between the two glass plates so as to spread to an area

A

. If

S

is the surface tension, then normal force required to separate the glass plates is

View answer and explanation

Correct option: B

\frac{2 S A^{2}}{V}

Option B (

\frac{2 S A^{2}}{V}

) is correct because it represents the normal force required to separate the plates, derived from surface tension and geometry.

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