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JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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What is the de-Broglie wavelength (in nm{nm} ) of an electron in the ground state of hydrogen atom is ?

Β [K.E.Β =13.6 eV;1 eV=1.602Γ—10βˆ’19Β JΒ ]Β \text { [K.E. }=13.6 \,{eV} ; 1 \,{eV}=1.602 \times 10^{-19} {~J} \text { ] }
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Correct option: A
0.33
Option A (0.33) is correct because it is the de-Broglie wavelength calculated using the kinetic energy of the electron.

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