$\mathop {\lim }\limits_{x \to 0} \left[ {\frac{{{2^x} - 1}}{{\sqrt {1 + x} - 1}}} \right]$ is equal to

JEE MATHEMATICS MCQ: LIMITS

1 Easy

1 of 1

Application +4 | -1

\lim\limits_{x \to 0} \left[ {\frac{{{2^x} - 1}}{{\sqrt {1 + x} - 1}}} \right]

is equal to

View answer and explanation

Correct option: C

{\log _e}4

Option C (

\log_e 4

) is correct because by applying L'Hopital's rule, the limit evaluates to ln(4).

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