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JEE PHYSICS MCQ: CURRENT ELECTRICITY

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The Earth's surface has a negative surface charge density of 135×10−9π(6.4)2C/m2\frac{135 \times 10^{-9}}{\pi(6.4)^2} \mathrm{C} / \mathrm{m}^2. The potential difference of 400kV400 \mathrm{kV} between the top of the atmosphere and the surface, results (due to low conductivity of the lower atmosphere) in a current of only 1800 A1800 \mathrm{~A} over the entire globe. If there is no mechanism of sustaining atmospheric electric field, how much time (in sec) would be required to neutralize the Earth's surface?(\left(\right. Radius of earth =6.4×106 m)\left.=6.4 \times 10^6 \mathrm{~m}\right)
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Correct option: D
283
Option B (4225\sqrt{\frac{42}{25}}) is correct because it is calculated by using the formula for the velocity of sound in a gas and taking the ratio for hydrogen and helium.

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