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JEE CHEMISTRY MCQ: AMINES

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Analyzing +4 | -1
Which of the following will produce isopropyl amine-

(I)(CH3)2CO→NH2OHX→LiAlH4({{I) (C}}{{{H}}_3}{)_2}CO\xrightarrow{{N{H_2}OH}}X\xrightarrow{{LiAl{H_4}}}

(II)CH3−CH2−CHO→heatNH3X→LiAlH4({{II) C}}{{{H}}_3} - C{H_2} - CHO\xrightarrow[{heat}]{{N{H_3}}}X\xrightarrow{{LiAl{H_4}}}

(III)(CH3)2CH−OH+PCl5→X→NH3({{III) (C}}{{{H}}_3}{)_2}CH - OH + PC{l_5} \to X\xrightarrow{{N{H_3}}}

(IV)CH3−CH2−CH2−NH2→heat({{IV) C}}{{{H}}_3} - C{H_2} - C{H_2} - N{H_2}\xrightarrow{{heat}}
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Correct option: C
I, III
Option C (I, III) is correct because both reactions produce isopropyl amine ((CH3)2CHNH2(CH_3)_2CHNH_2). Reaction I involves the reduction of an oxime derived from acetone, and Reaction III involves the reaction of isopropyl chloride with ammonia.

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