JEE MATHEMATICS MCQ: RATE MEASURE

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A particle moves along a straight line with the law of motion given by

{s^2} = a{t^2} + 2bt + c.

then the acceleration varies are

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Correct option: A

\frac{1}{{{s^3}}}

Option A (

\frac{1}{{{s^3}}}

) is correct because the acceleration is inversely proportional to the cube of the displacement, derived from differentiating the given equation of motion.

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