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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Analyzing +4 | -1
Let In=∫0π/4  tan⁡nx  dx,  (n>1  and  n∈N){I_n} = \int \limits_0^{\pi /4} \,\,{\tan ^n}x\,\,dx,\,\,\left( {n > 1\,\,\mathrm{and}\,\,n \in N} \right), then

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Correct option: B
In  +  In−2=  1n−1{I_n}\,\, + \,\,{I_{n - 2}} = \,\,\frac{1}{{n - 1}}
Option B is correct because the recurrence relation between In and In-2 is found to be In  + In−2=  1n−1{I_n}\,\,+ \,{I_{n - 2}} = \,\,\frac{1}{{n - 1}}.

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