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JEE PHYSICS MCQ: OSCILLATIONS

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A particle of mass

m

executes simple harmonic motion with amplitude

a

and frequency

\mathrm{v}

. The average kinetic energy during its motion from the position of equilibrium to the end is

View answer and explanation

Correct option: A

{\pi ^2}m{a^2}{\mathrm{v}^2}

Option A (

{\pi ^2}m{a^2}{\mathrm{v}^2}

) is correct because the average kinetic energy is calculated as

\frac{1}{4}m a^2 \omega^2

, where

\omega = 2 \pi v

.

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Assertion: A particle executing simple harmonic motion comes to rest at the extreme positions.

Reason: The resultant force on the particle is zero at these positions. A particle is subjected simultaneously to two SHM’s one along the

x

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y

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a

. When the PE of a particle is one-fourth of its maximum value during the oscillation, its displacement from the equilibrium position will be The displacement, velocity and acceleration in a simple harmonic motion are related as the Assertion: Angular velocity of earth around sun is lesser than the angular velocity of moon about earth.
Reason: Time taken by moon revolve around earth is less than time taken by earth to revolve around sun. A particle is executing

SHM

. At a displacement

{y_1}

its potential energy is

{U_1}

and at a displacement

{y_2}

its potential energy is

{U_2}

. The potential energy of the particle at displacement

\left( {{y_1} + {y_2}} \right)