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JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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Application +4 | -1
If the shortest wavelength of H-atom in Lyman series is x, the longest wavelength in Balmer series of He+\mathrm{H}{\mathrm{e}^ + } is
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Correct option: D
9x5\frac{{9x}}{5}
Option D (9x5\frac{{9x}}{5}) is correct because it is derived from using the Rydberg formula for the shortest wavelength in the Lyman series of H and the longest wavelength in the Balmer series of He+.

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