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JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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If 2tan⁡2x−5sec⁡x2 \tan ^2 x-5 \sec x is equal to 1 for exactly 7 distinct values of x∈[0,nπ2]n∈Nx \in\left[0, \frac{n \pi}{2}\right] n \in N, then the greatest value of nn is
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Correct option: D
15
Option D (15) is correct because the equation simplifies to sec(x) = 3, which yields 7 distinct solutions within the given interval, resulting in n=15.

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