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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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13!+25!+37!+…\frac{1}{{3!}} + \frac{2}{{5!}} + \frac{3}{{7!}} + \ldots is equal to
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Correct option: A
e−12\frac{{{e^{ - 1}}}}{2}
The correct answer is A (e−12\frac{{{e^{ - 1}}}}{2}) because the given series can be expressed as a difference of factorials, leading to a form related to the exponential function.

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