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JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1
If f(x+3y,x−3y)=12xyf(x+3 y, x-3 y)=12 x y, then f(x,y)f(x, y) is
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Correct option: C
x2−y2x^2-y^2
Option C (x2−y2x^2-y^2) is correct because substituting x+3yx+3y and x−3yx-3y into x2−y2x^2 - y^2 yields the given expression 12xy12xy.

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