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JEE CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

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The percentage weight of ZnZn in white vitriol [ZnSO4ā‹…7H2O]\left[ZnSO_4 \cdot 7H_2O\right] is approximately equal to (Zn=65, S=32, O=16 and H=1)\left(Zn=65, \, S=32, \, O=16 \, \text{and} \, H=1\right)
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Correct option: D
22.65%22.65 \%
Option D (22.65%22.65 \%) is correct because it is calculated by dividing the mass of Zn by the molecular weight of the compound and multiplying by 100.

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