Skip to main content
Back to CURRENT ELECTRICITY

JEE PHYSICS MCQ: CURRENT ELECTRICITY

1 Medium
1 of 1
Application +4 | -1
The resistance of a wire is ′R′'R' ohm. If it is melted and stretched to ′n′'n' times its original length, its new resistance will be
View answer and explanation
Correct option: D
n2R{n^2}R
Intensity at y=0.4 mmy=0.4 \mathrm{~mm} is zero. This is because at y=0.4y=0.4 mm, the path difference corresponds to an odd multiple of λ/2\lambda/2, resulting in destructive interference.

More Questions from CURRENT ELECTRICITY

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.