NEET UG PHYSICS MCQ: ALTERNATING CURRENT

Option A (${E^2}R/ {{R^2} + {{\left( {L\omega - \frac{{1}}{{C\omega }}} \right)}^2}} )$ is correct because it represents the power dissipated in an LCR series circuit, derived from the formula $P = \frac{{E^2}}{Z} \cos \phi$, where Z is the impedance and $\cos \phi$ is the power factor.