JEE MATHEMATICS MCQ: MAXIMA & MINIMA

1 Easy

1 of 1

Analyzing +4 | -1

For any real

\theta

, the maximum value of

\cos ^2(\cos \theta)+\sin ^2(\sin \theta)

View answer and explanation

Correct option: B

1+\sin ^2 1

Option B is correct because the maximum value of

\cos^2(\cos \theta)

is 1, and the maximum value of

\sin^2(\sin \theta)

\sin^2(1)

, both occurring at

\theta = \frac{\pi}{2}

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f(x)=\left(1+b^2\right) x^2+2 b x+1

m(b)

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b

m(b)

f: R \rightarrow R

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x<0

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p

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\frac{k}{e}

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