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JEE MATHEMATICS MCQ: LIMITS

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Analyzing +4 | -1
Let f(x)f(x) be a polynomial of degree 4 having extreme values at x=1x=1 and x=2x=2. If lim⁡x→0(f(x)x2+1)=3\lim _{x \rightarrow 0}\left(\frac{f(x)}{x^2}+1\right)=3 then f(−1)f(-1) is equal to
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Correct option: D
92\frac{9}{2}
Option D (92\frac{9}{2}) is correct because after finding the polynomial f(x) using the given conditions, f(-1) evaluates to 92\frac{9}{2}.

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