JEE MATHEMATICS MCQ: LIMITS

1 Hard

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Analyzing +4 | -1

\lim\limits_{{x \rightarrow -\infty}}\frac{x^5 \tan \left(\frac{1}{\pi x^2}\right)+3|x|^2+7}{|x|^3+7|x|+8}

is equal to 

View answer and explanation

Correct option: A

-\frac{1}{\pi}

Option A (-1/π) is correct because after dividing by |x|^3 and using the limit tan(θ)/θ as θ approaches 0, the expression simplifies to -1/π.

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