JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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A dye absorb light of

\lambda=4530 \mathop {\text{A}}\limits^{\text{o}}

and then fluorescence of

5080 \mathop {\text{A}}\limits^{\text{o}}

Assuming that under given conditions

47 \% \mathrm{C}

absorbed energy is re-emitted out as fluorescence, calculate ratio of quanta emitted out to the number of quanta absorb

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Correct option: A

0.527

Option A (0.527) is correct because it represents the ratio of emitted to absorbed quanta, calculated using the wavelengths and the given energy conversion efficiency.

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