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JEE PHYSICS MCQ: MAGNETIC EFFECT OF CURRENT

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Application +4 | -1
A proton carrying 1 MeV kinetic energy is moving
in a circular path of radius RR in uniform magnetic
field. What should be the energy of an a-particle
to describe a circle of the same radius in the same
field?
View answer and explanation
Correct option: B
1 MeV
Option B (1 MeV) is correct because the energy of the alpha particle is equal to the energy of the proton when they have the same radius in the same magnetic field.

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