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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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If log⁡2x+log⁡24x+log⁡26x+…+log⁡232x=136\log _{\sqrt{2}} x+\log _{\sqrt[4]{2}} x+\log _{\sqrt[6]{2}} x+\ldots+\log _{\sqrt[32]{2}} x=136, then x=x=
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Correct option: B
2\sqrt{2}
Option B (2\sqrt{{2}}) is correct because it is the value of x that satisfies the given logarithmic equation, found by simplifying the equation using logarithm properties.

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