The following mechanism has been proposed for the reaction of ${\rm{NO}}$ with ${\rm{B}}{{\rm{r}}_2}$ to form $NOBr$ ${\rm{NO}}\left( {\rm{g}} \right) + {\rm{B}}{{\rm{r}}_2}\left( {\rm{g}} \right)\leftrightharpoons{\rm{NOB}}{{\rm{r}}_2}\left( {\rm{g}} \right)$ ${\rm{NOB}}{{\rm{r}}_2}\left( {\rm{g}} \right) + {\rm{NO}}\left( {\rm{g}} \right) \to 2{\rm{NOBr}}\left( {\rm{g}} \right)$ If the second step is the rate determining step, the order of the reaction with respect to ${\rm{NO}}\left( {\rm{g}} \right)$ is

JEE CHEMISTRY MCQ: CHEMICAL KINETICS

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The following mechanism has been proposed for the reaction of

\mathrm{NO}

with

\mathrm{B}{\mathrm{r}_2}

to form

NOBr

\mathrm{NO}\left( \mathrm{g} \right) + \mathrm{B}{\mathrm{r}_2}\left( \mathrm{g} \right)\leftrightharpoons\mathrm{NOB}{\mathrm{r}_2}\left( \mathrm{g} \right)

\mathrm{NOB}{\mathrm{r}_2}\left( \mathrm{g} \right) + \mathrm{NO}\left( \mathrm{g} \right) \to 2\mathrm{NOBr}\left( \mathrm{g} \right)

If the second step is the rate determining step, the order of the reaction with respect to

\mathrm{NO}\left( \mathrm{g} \right)

View answer and explanation

Correct option: D

Option D (2) is correct because the rate law, derived from the rate-determining step and equilibrium, shows a second-order dependence on

\mathrm{NO}