Question

If $M(A ; Z), M_p$ and $M_n$ denote the masses of the nucleus ${ }_{\mathrm{Z}}^{\mathrm{A}} \mathrm{X}$, proton and neutron respectively in units of $\mathrm{u}(1 \mathrm{u}=$ $931.5 \mathrm{~MeV} / \mathrm{c}^2$ ) and $\mathrm{BE}$ represents its bonding energy in $\mathrm{~MeV}$, then

Accepted Answer

$\mathrm{M}(\mathrm{A}, \mathrm{Z})=\mathrm{ZM}_{\mathrm{p}}+(\mathrm{A}-\mathrm{Z}) \mathrm{M}_{\mathrm{n}}-\mathrm{BE} / \mathrm{c}^2$

Answer

$\mathrm{M}(\mathrm{A}, \mathrm{Z})=\mathrm{ZM}_{\mathrm{p}}+(\mathrm{A}-\mathrm{Z}) \mathrm{M}_{\mathrm{n}}+\mathrm{BE}$

Answer

$\mathrm{M}(\mathrm{A}, \mathrm{Z})=\mathrm{ZM}_{\mathrm{p}}+(\mathrm{A}-\mathrm{Z}) \mathrm{M}_{\mathrm{n}}-\mathrm{BE}$

Answer

$\mathrm{M}(\mathrm{A}, \mathrm{Z})=\mathrm{ZM}$ p $+(\mathrm{A}-\mathrm{Z}) \mathrm{M}_{\mathrm{n}}+\mathrm{BE} / \mathrm{c}^2$

JEE PHYSICS MCQ: NUCLEI

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