NEET UG CHEMISTRY MCQ: REDOX REACTIONS

1 Easy

1 of 1

Analyzing +4 | -1

Which of the following has been arranged in order of increasing oxidation number of Nitrogen

View answer and explanation

Correct option: C

NH_4^ + < {N_2}{H_4} < N{H_2}OH < {N_2}O

Option C (NH4+ < N2H4 < NH2OH < N2O) is correct because it correctly orders the compounds based on increasing oxidation numbers of nitrogen: -3 < -2 < -1 < +1.

More Questions from REDOX REACTIONS

Practice All Chapter MCQs →

The oxidation state of iron in sodium nitroprusside is : Titrations in which liberated

{I_2}

is estimated to carry out the volumetric estimations are known as ….titrations. It is found that V forms a double salt isomorphous with Mohr’s salt. The oxidation number of V in this compound is : For redox reaction,

\mathrm{MnO}_4^ - + {\mathrm{C}_2}\mathrm{O}_4^{2 - } + {\mathrm{H}^ + } \to \mathrm{M}{\mathrm{n}^{2 + }} + \mathrm{C}{\mathrm{O}_2} + {\mathrm{H}_2}\mathrm{O}

coefficient of reactants in balanced states are

\mathrm{MnO}_4^ -

{\mathrm{C}_2}\mathrm{O}_4^{2 - }

{\mathrm{H}^ + }

Which one of the following reaction is possible at anode? The couple having oxidised and reduced forms of a substance taking part in an oxidation or reduction half-reaction is called