JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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Application +4 | -1

The quantum number of four electrons are given below:
I.

n = 4,\,\,l = 2,\,\,{m_l} = - 2,\,\,{m_s} = - \frac{1}{2}

II.

n = 3,\,\,l = 2,\,\,{m_l} = 1,\,\,{m_s} = + \frac{1}{2}

III.

n = 4,\,\,l = 1,\,\,{m_l} = 0,\,\,{m_s} = + \frac{1}{2}

IV.

n = 3,\,\,l = 1,\,\,{m_l} = 1,\,\,{m_s} = - \frac{1}{2}

The correct order of their increasing energies will be

View answer and explanation

Correct option: C

\mathrm{IV < II < III < I}\,

The correct order is IV < II < III < I because the energy of an electron is determined by the (n+l) rule, and if (n+l) is the same, the electron with lower n has lower energy.

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