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JEE MATHEMATICS MCQ: LIMITS

1 Easy
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Analyzing +4 | -1
The value of lim⁡h→0ln⁡(1+2h)−2ln(1+h)h2\lim\limits_{h \to 0} \frac{{\ln \left( {1 + 2h} \right) - 2l\mathrm{n}\left( {1 + h} \right)}}{{{h^2}}} is
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Correct option: B
−1- 1
Option B (−1-1) is correct because using logarithm properties and limit evaluation, the expression simplifies to −1-1.

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