The number of oxygen atoms in $24.9 \mathrm{~g}$ of $\mathrm{CuSO}_4 \cdot 5 \mathrm{H}_2 \mathrm{O}$ is (molar mass of $\mathrm{Cu}=63 \mathrm{~g} \mathrm{~mol}^{-1}$)

JEE CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

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The number of oxygen atoms in

24.9 \mathrm{~g}

\mathrm{CuSO}_4 \cdot 5 \mathrm{H}_2 \mathrm{O}

is (molar mass of

\mathrm{Cu}=63 \mathrm{~g} \mathrm{~mol}^{-1}

)

View answer and explanation

Correct option: C

5.42 \times 10^{23}

The correct answer is

5.42 \times 10^{23}

because the number of oxygen atoms is calculated from the moles of the compound and the number of oxygen atoms per molecule.

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{H_2}O.

mol\,\,k{g^{ - 1}})

2.24 {~L}

{CH}_4

{CO}_2

0.5 \mathrm{M} \mathrm{H}_2 \mathrm{SO}_4

0.5 \mathrm{~g}

\mathrm{Cu}(\mathrm{II})