JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

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Application +4 | -1

a, b, c, d

are positive real numbers such that

a+b+c+d=2

, then

m=(a+b)(c+d)

satisfies the relation

View answer and explanation

Correct option: A

0 < m \leq 1

Option A (

0 < m \leq 1

) is correct because, by AM-GM inequality, the maximum value of (a+b)(c+d) is 1 when a+b = c+d = 1, and since a,b,c,d are positive, m > 0.

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