JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

1 Easy

1 of 1

Understanding +4 | -1

The angular momentum of an electron in a given stationary state can be expressed as

m_e v r=n \frac{h}{2 \pi}

. Based on this expression an electron can move only in those orbits for which its angular momentum is

View answer and explanation

Correct option: B

Integral multiple of

\frac{h}{2 \pi}

Option B (Integral multiple of

\frac{h}{2 \pi}

) is correct because Bohr's quantization condition states that the angular momentum of an electron is an integral multiple of

\frac{h}{2 \pi}

More Questions from STRUCTURE OF ATOM

Practice All Chapter MCQs →

n^{\text {th }}

\mathrm{A}

\times 10^{12}

\frac{1}{{ }^{\prime} \mathrm{B}^{\prime}}

\ell = 1,\,\,m = 0

1.25 \times {10^{ - 13}} \times {A^{1/3}}\mathrm{cm}.