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JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES
1
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Application
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Calculate the ratio of electric to gravitational force between two electrons.
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Correct option: A
Option A () is correct because it is calculated by dividing the electric force by the gravitational force between two electrons, using the respective formulas.
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Assertion:- Electric field lines do not cut at any point.
Reason:- At any point, there is only one direction of electric field. Statement-I: A positive point charge is brought in an electric field, the electric field at neary by point will increase
Statement-II: Electric field produced by charge may favour the existing electric filed Two particles having equal mass and charge
are separated by a distance The force(s) they
experience is (are) Statement-I: No 2 electric lines of force can intersect each other
Statement-II: tangent at any point of electric line of force gives the direction of electric field A force of is acting between two charges in air if the space between them is completely filled with glass , then the new force will be …… An electron is placed at centre of a conducting sphere of radius 0.2 metre having charge coulomb. The force of on the electron is ________ N
Reason:- At any point, there is only one direction of electric field. Statement-I: A positive point charge is brought in an electric field, the electric field at neary by point will increase
Statement-II: Electric field produced by charge may favour the existing electric filed Two particles having equal mass and charge
are separated by a distance The force(s) they
experience is (are) Statement-I: No 2 electric lines of force can intersect each other
Statement-II: tangent at any point of electric line of force gives the direction of electric field A force of is acting between two charges in air if the space between them is completely filled with glass , then the new force will be …… An electron is placed at centre of a conducting sphere of radius 0.2 metre having charge coulomb. The force of on the electron is ________ N