The value of $\mathop {\lim }\limits_{x \to \infty } {\left( {\frac{{3x - 4}}{{3x + 2}}} \right)^{\frac{{x + 1}}{3}}}$ is equal to

JEE MATHEMATICS MCQ: LIMITS

1 Easy

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Application +4 | -1

The value of

\lim\limits_{x \to \infty } {\left( {\frac{{3x - 4}}{{3x + 2}}} \right)^{\frac{{x + 1}}{3}}}

is equal to

View answer and explanation

Correct option: B

{e^{ - 2/3}}

Option B (

{e^{ - 2/3}}

) is correct because by rewriting the expression and taking the limit as x approaches infinity, the result is

{e^{ - 2/3}}

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