Skip to main content
Back to STATISTICS

JEE MATHEMATICS MCQ: STATISTICS

1 Easy
1 of 1
Application +4 | -1
The weighted AM of first n natural numbers whose weights are equal to the corresponding numbers is equal to
View answer and explanation
Correct option: C
13(2  n+1)\frac{1}{3}\left( {2\;n + 1} \right)
Option C (13(2  n+1)\frac{1}{3}\left( {2\;n + 1} \right)) is correct because the weighted AM is calculated by dividing the sum of the products of the numbers and their weights by the sum of the weights.

More Questions from STATISTICS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.