Air is expanded form 50 litre to 150 litre at 2 atmospheric pressure (1 atm pressure = ${\bf{1}}{{\bf{0}}^{\bf{5}}}{\bf{kg}}{\rm{ }}{{\bf{m}}^{ - {\bf{2}}}}$). The external work done is

NEET UG PHYSICS MCQ: THERMODYNAMICS

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Application +4 | -1

Air is expanded form 50 litre to 150 litre at 2 atmospheric pressure (1 atm pressure =

\mathbf{1}{\mathbf{0}^\mathbf{5}}\mathbf{kg}\mathrm{ }{\mathbf{m}^{ - \mathbf{2}}}

). The external work done is

View answer and explanation

Correct option: C

2 \times {10^4}J

The external work done is

2 \times {10^4}J

because it is calculated using the formula

W = P\Delta V

, where P is the pressure and

\Delta V

is the change in volume.