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JEE MATHEMATICS MCQ: PERMUTATIONS

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Application +4 | -1
If an=∑r=0n1nCra_n=\sum\limits_{{r=0}}^n \frac{1}{{ }^n C_r}, then ∑r=0nrnCr\sum\limits_{{r=0}}^n \frac{r}{{ }^n C_r} equals:
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Correct option: A
n2an\frac{n}{2} a_n
Option A (n2an\frac{n}{2} a_n) is correct because by using the property nCr=nCn−r{}^nC_r = {}^nC_{n-r}, we can rewrite the sum and solve for the desired expression.

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