If $\sin \,\,{\rm{\theta }} = \sqrt 3 \,\,\cos \,\,{\rm{\theta }},{\rm{\;\pi }} < {\rm{\theta }} < 0$, then ${\rm{\theta }}$ is equal to

$ - \,\,\frac{{4{\rm{\pi }}}}{6}$

$ - \,\,\frac{{5{\rm{\pi }}}}{6}$

JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

1 Easy

1 of 1

Application +4 | -1

\sin \,\,\mathrm{\theta } = \sqrt 3 \,\,\cos \,\,\mathrm{\theta },\mathrm{\;\pi } < \mathrm{\theta } < 0

, then

\mathrm{\theta }

is equal to

View answer and explanation

Correct option: B

- \,\,\frac{{4\mathrm{\pi }}}{6}

Option A (

- \,\frac{{4\mathrm{\pi }}}{{6}}

) is correct because it satisfies the given equation

\sin \theta = \sqrt{3} \cos \theta

and the condition

\mathrm{\pi } < \mathrm{\theta } < 0

Practice All Chapter MCQs →

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