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JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

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Application +4 | -1

An electron moves a distance of

6 \mathrm{~cm}

when accelerated from rest by an electric field of strength

2 \times 10^4 \mathrm{~NC}^{-1}

. Calculate the time of travel. The mass and charge of electron are

9 \times 10^{-31} \mathrm{~kg}

and

1.6 \times 10^{-19} \mathrm{C}

respectively.

View answer and explanation

Correct option: C

0.585 \times 10^{-8} \mathrm{~s}

Option C (

0.585 \times 10^{-8} \mathrm{~s}

) is correct because it is calculated using kinematics equations with the acceleration derived from the electric field force.

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