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JEE PHYSICS MCQ: ELECTRIC POTENTIAL AND CAPACITANCE

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A parallel plate capacitor of plate area AA and plate separation dd is charged to potential VV and then the battery is disconnected. A slab of dielectric constant kk is then inserted between the plates of the capacitors so as to fill the space between the plates. If Q,EQ,E and WW denote respectively, the magnitude of charge on each plate, the electric field between the plates (after the slab is inserted) and work done on the system in question in the process of inserting the slab, then state incorrect relation from the following
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Correct option: D
W=ε0AV22d(1−1k)W = \frac{{{\varepsilon _0}A{V^2}}}{{2d}}\left( {1 - \frac{1}{k}} \right)
Option D is the incorrect relation because the work done should be negative, indicating work done *by* the system, not *on* the system.

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