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JEE MATHEMATICS MCQ: STATISTICS

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Application +4 | -1
For the given data, the calculation corresponding to all values of variates (x,y)\left( {x,y} \right) is following   ∑(x−xˉ)2=36,  ∑(y−yˉ)2=25,  ∑(x−xˉ)(y−yˉ)=20\;\sum {\left( {x - \bar x} \right)^2} = 36,\;\sum {\left( {y - \bar y} \right)^2} = 25,\;\sum \left( {x - \bar x} \right)\left( {y - \bar y} \right) = 20. The Karl Pearson’s correlation coefficient is
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Correct option: C
0.66
Option C (0.66) is correct because it is the calculated Karl Pearson's correlation coefficient using the given data.

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