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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Analyzing +4 | -1
Let f:[0,5]→Rf:[0,5] \rightarrow R such that f(1)=3f(1)=3 and g(x)=∫1xtf(t)dtg(x)=\int_1^x t f(t) d t.If F(x)=∫0xx2g(x)F(x)=\int_0^x x^2 g(x), then F(x)F(x) has
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Correct option: A
a local minimum at x=1x=1
Option A is correct because F''(1) > 0, indicating a local minimum at x=1 after applying the fundamental theorem of calculus and given conditions.

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