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JEE MATHEMATICS MCQ: PROBABILITY

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If P(A∪B)=0.8P\left( {A \cup B} \right) = 0.8 and P(A∩B)=0.3,P\left( {A \cap B} \right) = 0.3, then P(A′)+P(B′)P\left( {A'} \right) + P\left( {B'} \right) equals to
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Correct option: D
0.9
Option D (0.9) is correct because it is calculated using the properties of probability and De Morgan's laws.

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