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JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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The de Broglie's wavelength of electron present in first Bohr orbit of H\mathrm{H} atom is
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Correct option: B
2π×0.529 A∘2 \pi \times 0.529 \, \mathop {\text{A}}\limits^ \circ
The correct answer is B; 2π×0.529 A∘2 \pi \times 0.529 \, \mathop{{\text{A}}}\limits^ \circ. The de Broglie wavelength is equal to the circumference of the first Bohr orbit.

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