$100 \mathrm{~mL}$ of $10 \% \mathrm{~NaOH}(w / \mathrm{V})$ is added to $100 \mathrm{~mL}$ of $10 \% \mathrm{HCl}(w / \mathrm{V})$. The resultant solution becomes:

JEE CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

1 Medium

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Analyzing +4 | -1

100 \mathrm{~mL}

10 \% \mathrm{~NaOH}(w / \mathrm{V})

is added to

100 \mathrm{~mL}

10 \% \mathrm{HCl}(w / \mathrm{V})

. The resultant solution becomes:

View answer and explanation

Correct option: C

acidic

Option C (acidic) is correct. The number of moles of HCl is greater than the number of moles of NaOH, resulting in an acidic solution.

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