JEE MATHEMATICS MCQ: PROBABILITY

1 Easy

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Analyzing +4 | -1

The probabilities of three events

A, B

and

C

are given

P(A)=0.6, P(B)=0.4

and

P(C)=0.5

. If

P(A \cup B)=0.8

P(A \cap C)=0.3, \quad P(A \cap B \cap C)=0.2, \quad P(B \cap C)=\beta \quad

and

P(A \cup B \cup C)=\alpha

, where

0.85 \leq \alpha \leq 0.95

, then

\beta

lies in the interval

View answer and explanation

Correct option: C

[0.25,0.35]

Option C (

[0.25,0.35]

) is correct because it represents the interval in which the probability of the intersection of events B and C lies, derived from the given probabilities and the properties of probability.

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