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JEE MATHEMATICS MCQ: PERMUTATIONS

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Analyzing +4 | -1
If 29!+23!7!+15!5!=2ab!\frac{2}{9 !}+\frac{2}{3 ! 7 !}+\frac{1}{5 ! 5 !}=\frac{2^a}{b !}, where a,b∈Na, b \in N, then the ordered pair (a,b)(a, b) is
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Correct option: A
(9,10)(9,10)
Option A ((9,10)) is the correct answer because the given expression can be simplified and expressed in the form 2ab!\frac{2^a}{b !} where a=9 and b=10.

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